160+44t-16t^2=0

Solution for 160+44t-16t^2=0 equation:

160+44t-16t^2=0

a = -16; b = 44; c = +160;
Δ = b2-4ac
Δ = 442-4·(-16)·160
Δ = 12176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{12176}=\sqrt{16*761}=\sqrt{16}*\sqrt{761}=4\sqrt{761}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(44)-4\sqrt{761}}{2*-16}=\frac{-44-4\sqrt{761}}{-32}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(44)+4\sqrt{761}}{2*-16}=\frac{-44+4\sqrt{761}}{-32}
$